I want when I click on a link in my domain like http://example.com that my application is open. I understood that deep linking is only with the custom scheme. Is it feasible with the scheme http or https. If so, how can I do this with Expo ???
Hey @drtapha. We don’t support configuring that in standalone apps right now. If you detach you can definitely do that!
Thanks !!
I did what you told me. it works but Linking.getInitialURL() return the url launcher of expo exp0ba53f5179f841ecbc9dc2592d49b013://192.168.100.9:19000.
Look my android manifest
<activity
android:name=".LauncherActivity"
android:exported="true"
android:launchMode="singleTask"
android:screenOrientation="portrait"
android:theme="@android:style/Theme.Translucent.NoTitleBar">
<intent-filter>
<data android:scheme="example"/>
<action android:name="android.intent.action.VIEW"/>
<category android:name="android.intent.category.DEFAULT"/>
<category android:name="android.intent.category.BROWSABLE"/>
</intent-filter>
<intent-filter >
<action android:name="android.intent.action.VIEW" />
<category android:name="android.intent.category.DEFAULT" />
<category android:name="android.intent.category.BROWSABLE" />
<!-- Accepts URIs that begin with "http://www.example.com/gizmos” -->
<data android:scheme="http"
android:host="www.example.ma"
/>
<!-- note that the leading "/" is required for pathPrefix-->
</intent-filter>
</activity>
Linking.getInitialURL
doesn’t know about your change to AndroidManifest.xml, so you should just construct the url yourself.
Okay @jesse . But when opening the application I can not get the link from the browser.
how can i construct the url ???
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